SOLUTION soon: allprops10 starts here, with start from allprops09: allprops1055, for brief visit scroll to SIMPLIFIED SUMMARY SOLUTION
Don't be spooked by my filenames or value names they will become clear as you go:
Review of values and value names established by construction, the first construction being the pentagon and pentangle, which begins with the tangent = 2, or A=2, B=1,
being the most reliable beginning because the 1 is not arbitrary. It is one-half of two by construction, not by designation.
Pi, = pi = 3.141592654, all values accurate to 9th decimal place as is accepted as the standard level of precision for a hand-held calculator. * means multiply, / means divide
Phi, = 2 times (cos 36), = 2 * 0.809016994 = 1.618033988
phi = little Phi, the inverse of phi, = 0.618033988, = 2 * (sin 18), = 2 * 0.309016994
Phi^2 = 2.618033988 (or 989), being Phi + 1, and sum of the infinite Fibonacci series
Pi*MQ or (Pi*MQ) = Phi^2 * 1.2 (6/5) = 2.618033988 * 1.2 = 3.141640786
[R= radius of circle, (inner tangent) circle = AC outer tangent square = AS
the AS always = Pi * R^2 * (4/Pi) or = 4 * R^2 Therefore:
if the area of the square = Pi * R^2, then the side S must = sqrt(Pi) * R.
Numerical text may not print as viewed. Try printer property adjustments. Or select (PDF of SOLCOMP 55)
FIRST: a bit of history, pages 1-4 here, a drop of the sea of my exploration of the entangled matrix of trigonometric ratios (proportion) (is everything) Pythagoras.
(Image75.gif)
New exploration: (inverses) (P. 1)
Pi* ZM^2 * MT^2 = (Pi*MT) * A , and MT * ZM^2 = 1 * B
MT ZM^2 B Pi * ZM^2 MT^2 (Pi*MT) A
Pi * 5 * MT = AC = 0.2082019131 * 4 = 729 = 0.265090909
24 Pi * ZM^2 (5/24)*(MT/ZM^2) Pi 2750
* MT^2 = 1375 = 0.2652391975 = 4 * A * 1 AND INVERSE
ZM^2 5184 B (Pi*MT)
= (Pi * MT) * 24 = [ B ] (6/5) = 3.770181818 [P. 1]
20 [4*A]
AS = Pi*MT * 6 , AC = Pi * (Pi*MT) * 3 = 1296 , = 4 * TN = 3.7701818181
5 10 1375 RA^2
= 4 * 0.942545454, 3.770181818 = (Pi*) 1.2 * MT = Pi * 1.200086145
MQ = 10 * Pi *RA^2 , Pi*MQ = 10 * RA^2, Pi* MQ*MQ =Pi*MQ^2
3 3 HO HO
= 10 * MQ , MQ^2 = 10 * MQ , as Pi * Pi*MQ^2 = AC
3 HO*RA^2 3 Pi*HO*R^2 HO
AS = 4 * Pi*MQ^2 = 40 * MQ , 3.138678857, * Pi = 9.860450439
HO 3 * HO*RA^2
* 4 = 12.55471543 = 40 * MQ confirmed, MQ^2 = 10 * MQ **
3 * HO*RA^2 HO 3 *Pi*HO*RA^2
=0.9990725098, * Pi = Pi*MQ^2 ! HO = 3 * (Pi*HO)* RA^2 = AC
HO MQ^2 10 MQ
if AC = 1.000928351, AS = 1.274421558, * Pi = 4.003713405, 4 * HO
MQ^2
New path: 20 * 1.728 * 6 = 120 * 216 = 320 = 11.851851851
11 5 55 125 27
320 = 11.85185185185 * 2187 = 3.7701818181 and (Pi*MT) * 6
27 6875 5
= 320 * MT = 3.770181818, * Pi = 11.8443755, the same as AC
27 Pi * ZM^2
320 * MT , confirmed, = an AC, and the AS = 15.080727272
27 ZM^2
= 4 * 3.770181818, AND if AS = Pi^2 *ZM^2 * 6 = 320
5 27
then the AC = 9.308422677, = Pi * 80 = Pi * 2.962962962
27
AND 15.080727272 = (Pi*MT) * 24 , and Pi * MT * 320 = 11.8443755
5 Pi*ZM^2 27
because = MT * 320 = 3.77018181818 = 5184 = (Pi*MT) * 6 *****
Pi * ZM^2 27 1375 5
Pi * MT * 320 = 11.8443755 = AC , then AS = Pi * MT * 4.8
Pi* ZM^2 27
= AS = 24 * MT * 320 = 24 * (Pi*MT) OR XXXXXX
6 Pi* ZM^2 27 5
6 * (Pi*MT) = MT * 320 (both sides * X still equal *****
5 Pi* ZM^2 27 Y
and Pi * (Pi * MT) * 6X = MT * 320X (2/3) -- 7.896250335
5Y ZM^2 27Y
Pi^2 * MT * 6X = MT * 320X , Pi^2 = 800 * 1
5Y ZM^2 27Y 81 ZM^2
= AS = 4 * MT * 320 = 4 * 6 * (Pi*MT)
Pi* ZM^2 27 5
Pi * MT * 320 = AC, = 11.8443755, and Pi * 4 MT * 320
Pi * ZM^2 27 Pi * ZM^2 27
= 4 * MT * 320 = 47.37750201 = 4 * AC , Pi * 15.080727272
ZM^2 27
also 47.37750201 = 16 * 2.961093876, or 16 * 80 * MT xx
27 ZM^2
* 4 = 16 * MT * 320 = 4 * AC2, = 15.0807272, = 16 * 0.942545454
Pi Pi * ZM^2 27
4 * 11.8443755 = Pi * 15.080727272 ???? ALGORITHM? :
4 * MT * A = 4 * AC = 4 * Pi * R^2
ZM^2 B
xx Pi * MQ*MT = Pi * MQ^2 * TN = 3.139658986
ZM^2 ZM^2
4 * MT * 80 = 11.8443755, * 4 = 4 * AC or 4 * (Pi*R^2)
ZM^2 27
= Pi * 15.080727272, AS = 60.322909090, Pi * 19.20137833
=Pi * (Pi*MT) * 4.8, = 19.2 * (Pi * MT), or Pi * 19.2 * MT XXXXXX
AMAZINGLY, cos 36 = sqrt(Pi) * 5 ] = 0.809016994 = sqrt(Pi * 0.2083333333)
sqrt(MQ) 24 1.000007661
= 0.8090107969, = sqrt(Pi * 0.4564354646) = 0.6544984695, sqd = Pi * 5
24
4 * 5 = 5 , = AS , AND
24 6
Phi^2 = 0.6544984695 = Pi * 5 , = Pi * Phi^2
4*MQ 24 Pi * MQ*4
6875 = 96700 = ZM^2 = 800 * 275*Pi
2187*Pi 96639 MT 81 * Pi^2 864
= 800 * 275 * 1 = 220000 = 6875 = 96700 Confirmed
81 * 864 * Pi 69984 2187*Pi 96639
Pi * ZM^2 * MT^2 = (Pi*MT), = (Pi^2 * ZM^2) * MT
MT ZM^2 Pi * ZM^2
(Pi*MT) * 6 = MT * 320 = 3.7701818181818
5 Pi * ZM^2 27
NEXT ? : Table of pi-line factors Pi*X * A = X . NEXT: re-direct:
B Y
From this stage of my research, I jumped ahead to the conclusive discovery:
SIMPLIFIED SUMMARY SOLUTION: SOLITU COMPLETED or (Simplified Summary PDF)
An elaborate demonstration by calculation and then by construction is included here below. For those who are in a hurry, and for experienced geometers, immediately below is a summary statement of the solution, accomplished by an algebraic equality that is visible as a lost secret that was hidden in plain sight. The expression itself and the usefulness of similar right triangles is self-evident. One does not even need to pick up a compass and straightedge to see that the solution is COMPlete and correct:
Phi ^2 = 2.618033989, 47 = 1.044444444, 1 = 0.3819660113
45 2.618033989
4.7 = sqrt(0.5) , that * sqrt(2) = 1 and by numerical values:
4.5*Phi^2 sqrt(Pi) sqrt(Pi)
4.7 = 0.7071067812 = 0.3989422784 or 0.389422804 depending
4.5*2.618033989 1.772453851
on the hardware of your calculator. That * 1.414213562 =0.5641895835
which is 1 over the square root of pi. This means that all we need to do is construct a right triangle with A = X and B = 1 for the angle that produces Tangent = X. Next, if we reconstruct the controlling angle in order to construct a similar right triangle, and we use the compass and straightedge to make the Base B = 0.5641895835. We know that with
this reconstruction A = B * T or A = 1 * X or X , and then we use
sqrt(Pi) sqrt(Pi)
Altitude A as the radius R of our circle. Therefore, Pi*R^2 = X^2 for all X. Clearly,
we have the procedure, using only the compass and straightedge, to construct circles with an area of exactly X^2, which we know without any further labor that X^2 is a square with Side S = X exactly equal to the constructed circle. If one has the time and desire, continue to study the complete description of the calculations and constructions.
SOLUTION BEGINS HERE: NEW EXPLORATION: Finally after 55 years and hundreds of searches into different combinations of proportions, the solution that meets the requirements of the Pythagorean riddle: We can construct a circle exactly equal in area to a given square:
A) Demonstration by calculation
B) Demonstration by construction (multiple constructions, inventory of values, ratios
C) Why this is possibly SOLITU, the Secret of Life in the Universe, and the marriage
of symmetry and asymmetry. Also, realization that only proportion exists in Nature
and number is bio-perception, as in electromagnetic spectrum is detected as color.
vibration is detected as voice, music, a physical event (waves, wind, collision).
D) Why this is probably the Hiram Key.
E) Why this is probably "disclosure," as in where Jesus said (Luke12:2): "For there is nothing concealed that will not be revealed, nor so hidden that it will not be made known." Also Mark 4:22, and Matthew 10:26.
F) Is this the most credible "alien artifact"?
A) Demonstration by calculation:
REVIEWING: cos 36 = sqrt(Pi * 5 ) = 0.809016994 = sqrt(Pi * 0.2083333333)
sqrt(MQ) 24) 1.000007661
= 0.8090107969, = [sqrt(Pi) * (0.4564354646)]^2 = Pi * 5 .
24
The facts immediately above prompt an exploration of the question: "Is there a means by which we can use the side of a square to obtain the radius of the circle that is exactly
equal in area to that given square?" The answer is "Yes."
By exploration, we see that the side of the equal square is = sqrt(Pi) * R.
Further, it follows logically that the length of the diagonal of the outer tangent square
AS is S * sqrt(2) , and by reference the calculation above shows that the square root of [Pi * (5/24)] = (cos 36)/sqrt(MQ), and we discover that the length of the radius R of the circle that is exactly equal to [Pi * (5/24)] (or square with Side S =0.8090107969) equals S * 0.3989422804 * sqrt(2) . In this case R= 0.4564354646. Let's call this new value (0.3989422804) "W" as in "Wonderful!" [ W = sqrt(0.5)/sqrt(Pi)]
The problem is that we cannot readily construct 1/(sqrt(Pi). However, upon further exploration we find that the sqrt(0.5)/sqrt(Pi) is equal to (4.7/(4.5 * Phi^2),
that is: 1.044444444 * 0.3819660113, = 0.3989422784 (= W), and in practice
we derive an algorithm (the AC = AS Algorithm): The 9.2 Solution:
For any given square, the radius R for the circle exactly equal in area to that square is equal to: S * W * sqrt(2), or R = S * W * sqrt(2)
Example: square with area 5, S = sqrt(5), 2.236067977, times W * sqrt(2) equals:
1.261566261 = R. R^2 = 1.591549431, * Pi = 5. There may be a slight difference
between the 8th and 9th decimal position in the value of W on one's calculator, which
is an indication that we are working at the limit of the precision level of the calculator - 9 decimal places. If tested on the highest precision calculators, this algorithm will be proven true (0.3989422784 / 0.3989422804 = 0.999999995)
Here is proof of the accuracy of the calculation:
(cos 36) , sqd = (cos 36)^2 = Pi * 5 , and Pi = Phi^2 * 6
sqrt(MQ) MQ 24 MQ * 5
thus: Pi* 5 = (cos 36)^2 = Phi^2 * 6 * 5 , >>> (cos 36)^2 = Phi^2
24 MQ MQ * 5 * 24 4
and further: 4.7 = W, = sqrt(0.5) and W * sqrt(2) = 1
4.5*Phi^2 sqrt(Pi) sqrt(Pi)
and where S = sqrt(pi) * R, then S * W * sqrt(2) = R confirmed
B) Demonstration by Construction
Referring to the "Background Constructions," we see that we have already constructed line lengths and ratios of 1.2 (6/5), Phi (1.618033988) and Phi^2 (2.618033988). I will show the construction of Phi^2 as a divisor, wherein 1/Phi^2 which also = phi^2, or (0.618033988)^2, if placed as a numerator in a ratio or line value = 0.3819660113.
Next we can construct the ratio (and line value) of (47/45). There are several ways to accomplish this goal, but I will show the one that I believe is the easiest and quickest.
(47/45) = (4.7/4.5) = 1.044444444. Here are the few simple steps: use the compass and straightedge to reconstruct the line length of 1, double to 2, double to 4, double to 8. Then use the compass and straightedge to add the line length of 1.2. We now have the line length of 9.2. Use the compass to mark off from the left end the line length of 4.
Then use the compass and straightedge to construct the numerical length of 4.5 on the line length of 9.2: Open the compass to a line length of 3. Then divide that line length in half to = a line length of 1.5. Use the compass to add the line length of 1.5 to the line length of 3. Thus we have the line length of 4.5 on the line length of 9.2, meaning that the remaining length must be 4.7. Use the compass and straightedge to construct the right triangle with Altitude A = 4.7 and Base B = 4.5. The Tangent ratio of this right triangle is clearly (4.7/4.5) or 1.044444444, the same as (47/45).
Construction of (4.7/4.5):
|--------|--------|--------|--------|--------|--------|--------|--------|--------|- 9.2
0 1 2 3 4 ^ 5 6 7 8 9
| < 4.5 > | < 4.7 > |
Next: Altitude A = 4.7, Base B = 4.5,
[Image78.gif]
Tangent of the controlling angle G = 1.0444444444, and from our SRT Tables
(similar right triangles) we will use: When B = X, then A = X*T
First we use the common construction for reconstruction of an angle, which is shown
in any online search, to reconstruct controlling angle G to the lower right.
Then use the compass to mark off the end point for Base B for a length of (phi)^2
0.3819660113. Construct a perpendicular at the left end point of B to create the new
Altitude A, which must be, according to the axioms of Geometry = 0.3989422784
Reconstructed right triangle for angle G [46.24536427 deg], with Base B
constructed as the line length = 0.3819660113, A = W = 0.3989422804
[Image78.gif]
We know that we now have a line length of W = 0.3989422804, and we know that we can construct the ratio of Tangent = 0.3989422804 by constructing a right triangle with Altitude A = 0.3989422804 and Base B = 1.
We are ready to show our teacher Pythagoras that we were awake when he was teaching us under the shade of an olive tree in Syracuse, Sicily (Greek colony) in 500 BCE.
First we look again at our initial right triangle with Tangent = 2, inside the circle, where
we know the length of Hypotenuse H must be sqrt(5) (2.236067977) and we can construct the ratio with numerical value of 2.236067977 by constructing a right triangle where we construct Altitude A = sqrt(5) and Base B = 1.
And now, we use our compass and straightedge to construct a square with Side S equal to our square root of 5 (2.236067977), the square area being of course 5 exactly. Next we need to construct the radius R for our circle that has an area of 5 exactly.
IMPORTANT NOTE: If 0.3819660113 and W = 0.3989422804 are inconvenient lengths to construct (because they are small values), just multiply the 0.3819660113 by 4, to get 1.527864045, or by 8 to get 3.05572809, and then at the end stage of the calculation by construction simply divide by 4, or by 8 accordingly.
Another approach, perhaps easier, is to use a large sheet of poster or easel paper on a large flat table and begin the constructions with dimensions where the constructed line lengths of 2 and 1 (Tangent = 2) are approximately 6 inches and 3 inches. Proceeding forward then, any value in the vicinity of 1/3 of "one," such as 0.3819660113 and 0.3989422804, will be proportionally near the working value of one inch, a compass distance more manageable for a classroom compass or typical drafting compass. There is also an elegant and precise compass known as a bar
compass that opens and closes to precise line lengths.
Next, as stated, we construct a square with area equal to 5 exactly. This we accomplish simply and promptly by opening our compass to the line length that is the hypotenuse H
of our initial right triangle with Tangent = 2, being exactly sqrt(5).
On a straight horizontal line of suitable length we use our compass to mark off the lower side having the length of sqrt(5), then we construct two perpendiculars one at each end of our line = sqrt(5). And then we mark the line length of sqrt(5) on each of the vertical perpendiculars and then the top horizontal side of the square which now encloses the area equal to 5 exactly, where each side S = sqrt(5).
Square with side S = sqrt(5), area = 5, diagonal D = 3.16227766
(ImageCeqS.gif)
Side S = 2.236067977 [the outer circle is not the equal circle]
Next we take an obvious shortcut. We have seen that our target value is S * W * sqrt(2), which is expected to be the target value for radius R that generates the circle with area exactly equal to 5. Since we have a square with side S = to 2.236067977 we know that the diagonal of that square will have the length = to 2.236067977 * sqrt(2). Therefore, to quickly obtain our target value of S * W * sqrt(2), we use the diagonal and multiply that diagonal by the ratio value of W (0.3989422804).
We construct the ratio of Tangent = W = 0.3989422804 by constructing a right triangle with Altitude A = 0.3989422804 and Base B = 1.
(Image156.gif)
A = 0.3989422804, B = 1
Our diagonal of the square area = 5 is sqrt(5) * sqrt(2) = 3.16227766, recognizable as the sqrt(10), and that line length value times the Tangent = 0.3989422804 = 1.261566261 [when B = X, then A = X*T].
Thus, we reconstruct the controlling angle of our Tangent = 0.3989422804 (right triangle) to the right, and we then use our compass to mark off the length of sqrt(10) to serve as the length of Base B (3.16227766), and then raise the perpendicular side from the left end point of Base B. This makes the Altitude A = to B * T = 1.261566261. And this Altitude A = 1.261566261 is our radius R for the exactly equal circle, because 1.261566261
squared = 1.591549431, and that * Pi = 5 exactly. Reconstruction:
(Image156.gif)
B = 3.16227766, A = 1.261566261
(Image60.gif)
Circle with Radius R = 1.26156621, Pi * R^2 = 5 exactly.
[area of this "inner square" is not equal to 5]
We have constructed a circle exactly equal in area to a given square. Significantly, this was not accomplished by way of a unique or magical procedure of construction, but because we discovered that:
4.7 = W = sqrt(0.5) and W * sqrt(2) = 1
4.5*Phi^2 sqrt(Pi) sqrt(Pi)
The inverse is equally useful: We can perform the "inverse" calculation and construction, which may be easier to construct due to the relative sizes of the lines, ratios and plane areas that need to be constructed. As follows: [ Z = (1/W) ]
4.5*Phi^2 = Z = sqrt(Pi) , and Z * sqrt(0.5) = sqrt(Pi)
4.7 sqrt(0.5)
11.78115295 = Z = 1.772453851 = 2.506628275, * 0.707106781 = 1.772453851
4.7 0.707106781
First we construct the right triangle where Tangent = 4.5 , then reconstruct the controlling 4.7
angle (43.75463573 deg) and make Phi^2 the Base B [A = B*T], which makes the Altitude A = 2.506628275. We then construct a square with the Side S equal to
2.506628275, wherein one half of the diagonal (distance from the center to a right
angle corner) will equal the square root of Pi (1.772453851). Then we construct a right triangle with Altitude A = sqrt(Pi) [1.772453851 and Base B = 1. Tangent = sqrt(Pi). Now we can reconstruct the controlling angle and make Base B = sqrt(X) [ such as sqrt(3): 1.732050808). And then we construct (raise) a perpendicular from the end of Base B. Then we see that due to A = B*T the new Altitude A must be equal to sqrt(3) * sqrt(Pi) or 3.069980124. We use our compass and straightedge to construct a square with the side S =3.069980124. The area of that square equals Pi*3 exactly, or 9.424777961.
Therefore we have again constructed a square and a circle exactly equal in area because we know that we can use sqrt(3) to serve as the radius R for the circle.
Any differences that appear in the readouts of standard hand-held electronic calculators will be resolved by reference to the algorithm and constructions using our most precise electronic math co-processors available to universities and government agencies.
Extension of constructions:
Going back to our original construction of a circle area = 5, we can observe that for any square and circle equal in area, the ratio of S (side of the square) to R (radius of the circle) will always be sqrt(Pi), as in 2.236067977 / 1.261566261 = 1.772453851. Therefore, using only our compass and straightedge, we can construct the right triangle with Altitude A = S and Base B = R. The Tangent of the controlling angle (I usually constructed the controlling angle to the right) will be sqrt(Pi) . Next we reconstruct the controlling angle and then use our compass to mark off the Base B as a length of 1. At the end point of the Base = 1 we construct (or raise) a perpendicular. We now have a right triangle with Altitude A = sqrt(Pi) because A = (B*T) or A = 1 * sqrt(Pi).
(Image61.gif)
A = 2.236067977 B = 1.261566261 Tangent = 1.772453851 [sqrt(Pi)]
Reconstruction:
B = 1 Tangent = sqrt(Pi) A = sqrt(Pi)
We have constructed a line length (A) equal to sqrt(Pi) Then we can construct a right triangle with Altitude A = (Pi*ZM), = 3.142696805, also = [sqrt(800)/9], and Base B equal to sqrt(Pi). The Tangent of the controlling angle equals sqrt(Pi) * ZM, or
1.772453851 * 1.000351462 or 1.773076802. We then reconstruct this new controlling angle and use our compass and straightedge to construct the Base B = 1. And then we know that the length of Altitude A must be sqrt(Pi) * ZM, 1.773076802 [A = B*T].
(Image61.gif
Reconstructed Tangent = sqrt(Pi)* ZM with B = 1
then A = 1.1773076802 [sqrt(Pi) * 1.000351462]
At this point, a viewer who has come this far should know the geometric process and trigonometric facts we are applying using only the compass and straightedge. We can use the information we have thus far to construct the following calculations:
sqrt(Pi)*ZM = ZM and then (Pi*ZM) = Pi
sqrt(Pi) ZM
and then Tangent = sqrt(Pi) times sqrt(X) for any sqrt(X), which can be the constructible Side S for any square that equals exactly Pi * X.
[A = Tangent sqrt(Pi) * any Base B where B = sqrt(X)] which we obviously can construct as a circle (Pi*X). I leave these last constructions for those who are able. This way some will actually join in the fun rather than just reading.
C) Why this is possibly SOLITU, the Secret of Life in the Universe, and the marriage of symmetry and asymmetry. Also, a realization that only proportion exists in Nature and number is bio-perception, as in electromagnetic spectrum is detected as color.
vibration is detected as voice, music, a physical event (waves, wind, collision).
The solution to the Pythagorean Riddle is scientifically sound evidence that there is no phenomenon of "number" in the real physical universe, only proportion. Number is the detection of proportion by a technological animal, by the neurological organ we call our brain. The universe begins with one (1). Then it divides into two (2), and that is the first proportion [our famous tangent with H = sqrt(5)], and the birth of the binary number "system." However, there are no numbers and no number systems. Technological animals detect proportion as number and we therefore have systems of notation, meaning systems for writing numbers (decimal, binary, trigonometric, abacus, quipu, toes). I cannot speak for intelligent biological entities because I am not one. Neither are you. Intelligent beings produce no "unintended consequences." The outcomes of their activities are only what they intend. No "mistakes." No "I didn't mean its." This may be the Secret of Life in the Universe because it is direct evidence, confirming evidence, that
we (dizzy technological animals) are highly susceptible to concluding that what we detect (perceive) is what the universe IS, but what we perceive is organic perceptions of forces and events entirely separate from what we perceive: wind, music, light, green, blue, five (a proportion), 3, 777.8, and so many others. The ancient quote of a Greek philosopher saying "Man is the measure of all things" is a translation error. The true and correct philosophical observation is "Man (and woman) is the measur ER of all things."
D) Why this is probably the Hiram Key. There is history, or some say a legend, that the architect employed by King Solomon to build the Temple in Jerusalem was Hiram Abiff, who was the most knowledgeable in Geometry and Trigonometry. And he was the last person to keep an important or sacred secret in Geometry (and or Trigonometry). This secret was lost when he died (or was assassinated). I suspect that the solution to the Pythagorean Riddle, presented here, is that long lost secret. I defer to Hebrew scholars (and Free and Accepted Masons) who are far more likely to know the pertinent facts that can provide confirmation or not. I have never been a Mason or Rosicrucian member.
I don't like secrets.
E) Why this is probably "disclosure," as in where Jesus said (Luke12:2): "For there is nothing concealed that will not be revealed, nor so hidden that it will not be made known." Also Mark 4:22, and Matthew 10:26. For UFO people, or "ancient alien theorists," DISCLOSURE means when whoever is controlling us acknowledges the truth that is hidden by secretive and manipulative behavior of people or beings that are more powerful than us. It might be something like a farmer explaining what a farm is to a chicken. The chicken might try real hard to understand, but then the corn is overwhelming. It is hard to overtly agree that even for the most intelligent humans we are probably learning impaired to some extent, which means unable to understand some things that are clear and simple to creatures that are just genetically smarter than we are.
It's like the little boy in the special school who got the nickname "Time Tweet." There is golden knowledge hidden in his nickname, because the source of his nickname is himself. Many times each day he would look at one of the teachers or attendants and say "Time Tweet." But all the old timers knew why he said "Time Tweet." It was because he was asking a question "(Is it) time to eat?" You see, he could not read a clock, and in order to know when it was time to eat, he had to ask, all day, because eating was one of the things he understood and enjoyed very much. This is absolutely a true story, and this child played a major role in my exploration of "time" and my eventual conclusion that there is no time that is abstract and separated from a given clock. If you do not clearly understand the clock, you have no concept of time.
This is what DISCLOSURE means to me:
First, Luis Elizondo said that disclosure is a process rather than an event.
A) From Jesus: We humans, who are technological animals, must protect the life supporting environment and all living things including other people of course or we will lose everything. It is kind of like saying that if we graduate from "technological animal" to "intelligent being" we will no longer cause irreparable damage by our mistakes and "unintended consequences." We will become intelligent beings eligible to join the "guardians of the sky" (heavens) and we will not kill anything other than what we mean to kill. No accidental killing. No "I didn't mean" it broken windows. No toxic waste, no poisons in food, no changes to the environment except changes directed by intelligent and benevolent plans. My book The Primacy of Stewardship is a detailed study of the parables of the New Testament, which ALL point to this concept.
B) Information that explains how beings far more intelligent than us have participated in our human development or evolution. When you have lived 82 years as I have, you might have a strong feeling that being more intelligent than a human being is actually not a great achievement. We may come to learn that we are learning impaired or defective, but still we are offered the opportunity to overcome our flaws and grow enough to join the fellowship of life's protectors. This is where science fiction meets reality.
C) In order to become intelligent beings we need to grasp a couple of important realities. One is that there is only proportion, and our brains detect proportions and we call those proportions "numbers." This is similar to electromagnetic wavelength being detected as colors and heat, and vibrations being detected as voice, music, sounds. A creature with a curious brain cannot join the fellowship of caretakers until they understand that what our brains formulate from what we detect, and the real causes of our detections are two entirely different things. Our senses are organic detectors. What we detect is what we perceive. I could go on, but this profound reality must be understood and accepted in order for a human civilization to graduate from farm animal to caretaker.
D) Two is that time is a fiction of consciousness. This may seem like an odd, or fantastic, or strange statement. It may seem like some kind of spiritual or religious idea. However, I would offer what I believe is the best way to get what this means: try to make a statement about time without making any reference to a clock. That is, all statements about time are statements about counting a type of event that occurs again and again at regular intervals. That is what time is always. There is no such thing as time that is somehow separate from independent of the counting of intervals. This is different in a very important and obvious way from other types of measurements. A stick has length whether we count inches (or feet or some other "unit"). Stones have weight (or mass) whether we weigh them with a scale or not. But there is no "time" if we are not counting. All clocks are natural clocks, the counting of an occurrence. If you are interested in exploring this further, look at my "Timeworks" and especially my somewhat long short story entitled "Crazy James Clocks."
E) Is this the most credible "alien artifact"?
In order to understand how we can construct a circle and square exactly equal in area one must have a very precise measurement of numbers, or proportions. A very precise calculation of what we call numerical values is required. Without a precise knowledge of, or notation of, the exact values of Phi (the Golden Mean), (47/45), Pi*MQ or Phi^2 * (6/5) = 3.142640786, or (20/11) * 1.728 = (3.1418181818) = (Pi*MT) = (864/275), and and (Pi*HO) 3.144605511 and (Pi*ZM) or 3.142696805 or sqrt(800)/9, and KNOWING
that none of these are pi exactly (3.141592654) one cannot know the true positive solution to the Pythagorean Riddle. How did a group of Greek "philosophers" in Syracuse, Sicily know numerical values to this level of precision 500 years before the lifetimes of Julius Caesar and Jesus? This also is part of disclosure.
I hope you have enjoyed this trip. It may seem long to you. Lots of reading. Imagine what it was like for me, searching for this revelation for 55 years. I feel like I would not exchange the trip I have completed for all the vacations in the world, for all the cruises or expeditions or safaris. I stayed home and visited the stars.